Solve for x. log(x) + log(x - 3) = 1 Please explain how you got the answer.
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Nnesha (nnesha):
familiar with log rules ?
OpenStudy (anonymous):
No I forgot them. That's why I need help with this. Can you help me?
Nnesha (nnesha):
quotient rule\[\large\rm log_b y - \log_b x = \log_b \frac{ x }{ y}\]
to condense you can change subtraction to division
product rule \[\large\rm log_b x + \log_b y = \log_b( x \times y )\]
addition ----> multiplication
power rule \[\large\rm log_b x^y = y \log_b x\]
Nnesha (nnesha):
so there is a plus sign which rule you should apply ?
OpenStudy (anonymous):
addition ----> multiplication
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OpenStudy (anonymous):
How do you know which number is b?
Nnesha (nnesha):
yep so change addition to multiplication
log is same so you can apply it
Nnesha (nnesha):
b is base
Nnesha (nnesha):
so log is same as log base 10 \[\huge\rm log = \log_{10}\]
OpenStudy (anonymous):
So is it log(x*(x-3))?
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OpenStudy (anonymous):
Or log(x^2-3x)?
Nnesha (nnesha):
yep right!!
OpenStudy (anonymous):
So what do you do with the 1?
Nnesha (nnesha):
now you have \[\huge\rm log (x^2 -3x) =1\]
next step
convert log to exponential form
OpenStudy (anonymous):
How do you do that again?
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