Question

Given 28.2 grams of an unknown substance, if the substance absorbs 2165 joules of energy and the temperature increases by 35 Kelvin, what is the specific heat of the substance?

2.14 x 106 J/g·K

2.19 x 100 J/g·K

5.73 x 10-4 J/g·K

2.69 x 103 J/g·K

If someone could tell me how to do it as well, it would be greatly appreciated.

Answer 1

\[q=mc \Delta T\]

Answer 2

q is energy, m is mass, c is specific heat, delta T is change in temp

Answer 3

So would the answer then be B?

Answer 4

If that is 2.19 x 10^0 J/(g K), yep :-)

Answer 5

Cool, thanks for your help!

Answer 6

No worries :-)