What is 1 1/2 x3
it is \[\huge 1\tfrac{1}{2}\times 3\]
yes
do you know how to write \[\huge 1\tfrac{1}{2}\] as an "improper fraction"? that is the first step
a little
so first we have do deal with the 1 x 2 portion so what's 1 x 2 ?
I got 3/2
good
correct.
then \[\frac{3}{2}\times 3\] completes it
remember "multiply" means multiply in the numerator (top) so \[\frac{3}{2}\times 3=\frac{3\times 3}{2}\]
\[\LARGE \frac{3}{2} \times 3 \] now all we have to do is to multiply \[\LARGE \frac{2}{2}\] to 3 so we can have fractions with the same numerator x.x
oh no!!!
i got 6
what?
@UsukiDoll c'mon! you know you do not need a common denominator to multiply fractions !!!
I also got 18
lets go slow
nugh. this guy -_-
sigh.. let me guess change 3/2 into a decimal and then multiply by 3 ?
no no just multiply
we are at this step \[\frac{3}{2}\times 3\] right?
6
there is no 6 in it
i multiplied and got 6
\[\frac{3}{2}\times 3=\frac{3\times 3}{2}\] where does the 6 come from?
then I multiplied and got 18
wait a sec. re-write this a bit. to what sat wrote
okay
in the numerator (top) you have \(3\times 3\) which is ?
9
right
so the numerator is 9 and the denominator is 2 which is 9/2
and in the denominator you have just the 2
okay
giving you \[\frac{9}{2}\] which you should probably then write as a mixed number since you started with mixed numbers
4 1/2
at the risk of repeating myself you do NOT find a common denominator when multiplying that is for addition or subtraction multiply means multiply, that is all
right
wow are you kidding me right now sat? \[\large \frac{3}{2} \times 3 \cdot \frac{2}{2}\] \[\large \frac{3 \times 6}{4} \rightarrow \frac{18}{4} \rightarrow \frac{9}{2}\]
that is \[\huge 4\tfrac{1}{2}\] is correct
@UsukiDoll you must be kidding me right?
okay
no. even with finding the common denominator we can still get the same result -_-
\[\frac{3}{2}\times 3\times\frac{100}{100}=\frac{3\times 300}{200}=4\tfrac{1}{2}\]
heck if I was given that option to do it that way, pfffffffft so be it XD
you are doing nothing but confusing the issue you can get an equivalent fraction for 3 by multiplying top and bottom by any number you choose, but you do not do that when multiplying
no I'm not. I'm making it easier by having common denominators all over the place, so I can simplify the numerator... combine the denominator and then reduce.
let me repeat myself you do NOT find a common denominator when multiplying you need that only for addition and subtraction multiply means multiply
\[\frac{a}{b}\times \frac{c}{d}=\frac{ac}{bd}\] that is all
ahahaha you just did fractions XD
yes of course
\[\frac{a}{b}\times c=\frac{ac}{b}\] also fractions
\[\frac{a}{b}\times \frac{c}{d}=\frac{ac}{bd} \] this is better.
they are the same, only in the second case \[\frac{a}{b}\times c\] you have \(d=1\) no common denominator needed
okay
exactly sat .. still using fractions XD
let me ask you @UsukiDoll do you really build up fractions when multiplying? how would you compute \[\frac{52}{17}\times 5\]?
\[\frac{52}{17}\times 5 \cdot \frac{17}{17}\] \[\frac{52}{17} \times \frac{85}{17} \rightarrow \frac{4420}{289} \]
at least you are being consistent!
some times people have different methods that still give you the same answer
why not \[\frac{52}{17}\times 5 \cdot \frac{23}{23}\]? that will work as well
@UsukiDoll is it right?\(3=\dfrac{3}{1}\)? why do we have the common denominator on multiplication ?
so agree with @Aliypop
i like \[\frac{52}{17}\times 5 \cdot \frac{1712}{1712}\]
so the answer is 52/17
\[\frac{52}{17}\times 5=\frac{52\times 5}{17}\]
so your real job is to compute \(52\times 5\) don't mess with mr 17
don't mess with mister inbetween?
so would I multiply
that's just some example fraction that they threw at me. the real answer is already done. Honestly that's what I was taught in elementary school and it worked well. NO one is going to force me to use whatever kind of jumbo shrimp thing they throw out there. If it worked millions of times, I'm not going to change it!
P.S \[ \frac{4420}{289} = 15.29\] \[\frac{52}{17}\times 5 = 3.058 \times 5 = 15.29\] oh look ! The same decimal value regardless of method. nughhhhhh. . . sorry for ranting but that had gone too far.
thank for so much for helping me @UsukiDoll
you're welcome @Aliypop :) It's after 4 am... I better get some sleep.
okay
night everyone.
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