Question

Algebruh.

Answer 1

1.) Describe the direction of the parabola and determine the y-intercept and zeros of
f(x) = 5x2 + 2x + 1



Find the vertex and the equation for the axis of symmetry of the parabola, showing your work, so Ray can include it in his coaster plan.

Answer 2

@satellite73 @sammixboo @Mertsj @NeonStrawsForever @ParthKohli @e.mccormick

Answer 3

leading coefficient is positive ( it is 5 ) so it opens up

Answer 4

So far I have The vertex is going straight down, it is an acute angle. The y-intercept is 1

Answer 5

the first coordinate of the vertex of \(y=ax^2+bx+c\) is \(-\frac{b}{2a}\)
in your case it is
\[-\frac{2}{2\times 5}=-\frac{1}{5}\]

Answer 6

that makes the axis of symmetry
\[x=-\frac{1}{5}\]

Answer 7

the vertex is not an angle, acute or otherwise

Answer 8

the vertex is a point
the first coordinate of that point is \(-\frac{1}{5}\)

Answer 9

the second coordinate of the vertex is what you get for \(y\) when you replace \(x\) by \(-\frac{1}{5}\)

Answer 10

I meant parabola.

Answer 11

Okay, here's what I have so far.

1.) Describe the direction of the parabola and determine the y-intercept and zeros of f(x) = 5x2 + 2x + 1

The parabola is going straight down, it is an acute angle, the y-intercept is 1.

Answer 12

I need to find the zeroes of f(x) = 5x2 + 2x + 1

Answer 13

@satellite73 @sammixboo @Empty @welshfella

Answer 14

@DarkMoonZ @DaBest21

Answer 15

well I can tell you there are no real zeroes to this