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Chemistry 14 Online
OpenStudy (anonymous):

Quick Chemistry question, please show work :) 3. If 25.0 mL of a 4.525 M solution of HCl was poured into 112.0 mL of distilled water, the concentration of the resulting solution is _________ M.

OpenStudy (photon336):

Do you know what molarity is?

OpenStudy (rushwr):

@Photon336 What is the answer u get for this !

OpenStudy (australopithecus):

Concentration 1*Volume 1 = Concentration 2*Volume 2 Volume 1 = 25.0mL Concentration 1 = 4.525M Volume 1 = 112.0 mL + 25.0mL Concentration 2 = ? use the formula above to solve for concentration 2 Note that you are diluting the solute so your concentration should go down so: Concentration 1 > Concentration 2

OpenStudy (photon336):

\[N _{a}V _{a} = N _{b}V _{b}\]

OpenStudy (photon336):

\[\frac{ N _{a} V _{a} }{ V _{b} } = N _{b}\] re arrange and solve for Nb your final concentration: @agree with australopithecus \[HCl _{aq} + H _{2}O _{l} --> H3O ^{+}(aq) +Cl ^{-} \] \[K _{a} HCL >>> 1 \] so virtually no acid left.

OpenStudy (australopithecus):

The pKa of HCl is -3 so it will dissociate 100%

OpenStudy (australopithecus):

Dissociation doesn't matter though in this question

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