Question

What is the foci of a graphed ellipse?

Answer 1

Form this ellipse into the general equation.
\[\frac{ x^2 }{ a^2 } + \frac{ y^2 }{ b^2 } = 1\]

Answer 2

The ellipse isn't at origin so you need to adjust a little, and use the foci formula
\[c^2=a^2-b^2\]
c = foci

Answer 3

Ok, so..is the general equation x^2/-1 + y^2/16= 1?and then use those a and b in the new formula?

Answer 4

The general equation for this ellipse looks like this
\[\frac{ (x-2)^2 }{ 3^2 } +\frac{ (y-2)^2 }{ 2^2 } = 1\]

Answer 5

\[c^2=3^2-2^2\]

Answer 6

5? That isn't one of my options.. I'm sorry I'm not understanding this. My options are

A) (2 - sqrt5 , 1) and (2 + sqrt5 , 1)


B) (2 - sqrt5 , 2) and (2 + sqrt5, 2)


C) (2, 1) and (-2, 1)

D) (-3, 1) and (3, 1)

Answer 7

Its square root 5

Answer 8

you need to get your vertex first

Answer 9

Your best bet is B

Answer 10

I didn't mean to be given the answer, but thank you