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Mathematics 14 Online
OpenStudy (anonymous):

box has 8 beads of the same size, but all are different colors. Tamy draws a bead randomly from the box, notes its color, and then puts the bead back in the box. She repeats this 3 times. What is the probability that Tamy would pick a red bead on the first draw, then a white bead, and finally a red bead again?

OpenStudy (anonymous):

1 over 4096 1 over 512 1 over 64 1 over 8

oregonduck (oregonduck):

the answer is d 1 over 8

OpenStudy (anonymous):

could u please explain?

OpenStudy (mathstudent55):

Each pick has a probability of 1/8 to end up a specific color.

oregonduck (oregonduck):

yup what he said he read my mind

OpenStudy (mathstudent55):

The probability of each pick being a specific color is 1/8.

OpenStudy (anonymous):

@oregonduck just went to a different question that had the answer. he didnt know

OpenStudy (mathstudent55):

The probability of three pick in a rwo being a specific color is 1/8 * 1/8 * 1/8

OpenStudy (mathstudent55):

Answer is not d

OpenStudy (anonymous):

oh ok so i have to multiply?

OpenStudy (mathstudent55):

Yes.

oregonduck (oregonduck):

C IS THE ANSWER THAN HAPPY:)

OpenStudy (mathstudent55):

The probability of three independent events happening in a row is the product of their individual probabilities.

OpenStudy (mathstudent55):

Answer is not c either.

OpenStudy (anonymous):

sry i had to step away @mathstudent55

OpenStudy (anonymous):

@welshfella please help

OpenStudy (welshfella):

its 1 divided by 8*8*8 8* 8 = 64 8*64 = ?

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