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Chemistry 7 Online
OpenStudy (photon336):

Question

OpenStudy (photon336):

#1

OpenStudy (photon336):

#2 just one question

OpenStudy (photon336):

#3

OpenStudy (photon336):

#4

OpenStudy (photon336):

#160 carbon tetra chloride would definitely be the lowest, b/c it has just a polar covalent bond. I think that would be a liquid. heat of fusion (s) --> (l).

OpenStudy (rushwr):

I think I'll go with C for that question cuz I feel that H2O must be having a high heat of fusion. H2O has H bonds so in order to break that we need greater amount of heat. But I'm not sre

OpenStudy (rushwr):

161 I'll go with answer C

OpenStudy (rushwr):

196 I'll go with 1st answer

OpenStudy (rushwr):

208 I'll go with D

OpenStudy (rushwr):

206 it is C

OpenStudy (photon336):

@sweetburger

OpenStudy (anonymous):

160. You need to consider the force of the intermolecular bond between different molecules. we have: CCl4 - it's a gas at room t, so it's so it's fusion temprature is much under 0C' H20- liquid at room t, the intermolecular forces are: van der vals and h-bond. They are are weak forces, and we know that it fusion t it's' little more than 0C' NaCl and Al2O3 are bouth salt, instad we had a inic bond, and it is much stronger than van der vals or h-bond (cuz it's the attraction between partial charges, while in ionic we have entire charge). I had no idea which had higher fusing point between two salt. But wiki told me Al2O3 (2000 C') while NaCl (800 C'). So it should be the answer A.

OpenStudy (photon336):

Like at first i thought hydrogen bonds was the strongest, but then it was heat of fusion i.e melting.

OpenStudy (anonymous):

160. i get it, Al2O3 had higher fusion t, cuz the atoms Al and O are much more eletronegative instade of Na and Cl. So following Coulombs law of the interaction between charged objects, the forse is stronger because the atoms are more charged.

OpenStudy (photon336):

got confused by that l\[Al _{2}O _{3}\] is ionic. so you consider charges? of ions

OpenStudy (photon336):

@Bozhena that formula only deals with the magnitude of charges right? how does that apply to the ionic compounds, don't you have to take into consideration r?

OpenStudy (photon336):

the way i understood that was that the smaller ions have greater attraction? b/c they can get closer

OpenStudy (anonymous):

yes, i mean. We need to know which between two salt has strongest intermolecular bond (cux it's the bond you break during the fusion). So you first need to find how much charg will had each salt.|dw:1438222995551:dw| Now you can see tha each molecule could be rappresented as |dw:1438223266787:dw| U need to employ much more energy to break the interaction of force 4 than 2

OpenStudy (photon336):

Question 206. 1 mol of every gas has 22.4L occupied of volume. \[\frac{ mol }{ 22.4L } = \frac{ 2mol }{ ? }\] 44.8 mol*L = mol(x) 44.8L = Volume

OpenStudy (photon336):

@Bozhena I see what you did for the first part.. the aluminum has a much greater electronegativity value so it's bond is going to be stronger.

OpenStudy (photon336):

how does columns law apply to this if we were to use that?

OpenStudy (anonymous):

196. The density is 2g/L, if you assume to have a conteiner of 1L, You can find g of gas. 2g/l * 1L= 2g You also have the mols, and you know that Molar Mass is expressed in g/mol. So 2g/1mol = 2g/mol The molecule which have MM=2g/mol is H2

OpenStudy (anonymous):

160. consider that at che atomic level r does not matter, so consider r constant (i mean it does metter but the diffrence is very very small). |dw:1438223761999:dw|

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