Help medal will be given!!!! Using the following equation, find the center and radius: x2 - 4x + y2 + 8y = -4 The center is located at (-2, -4), and the radius is 4. The center is located at (2, -4), and the radius is 4. The center is located at (-2, -4), and the radius is 16. The center is located at (2, -4), and the radius is 16.
@pooja195 could you help plz
convert to standard form by completing the square
x2 - 4x + y2 + 8y = -4 = (x - 2)^2 - 4 + (y + 4)^2 - 16 = -4 = (x - 2)^2 + ( y + 4)^2 = 16
so would it be B
compare this with standard form (x - a)^2 + (y - b)^2 = r^2 where center = (a,b) and r = radius
yes B
thank you could you help me with another im stuck on
ok
ABCD is a quadrilateral inscribed in a circle:What equation can be used to solve for angle D?
(2x + 16) + (6x - 4) = 90 (x + 16) - (x) = 90 (x + 16) + (2x + 16) = 180 (2x + 16) + (x) = 180
opposite angles of a cyclic quadrilateral add up to 180 degrees
what angle is opposite D?
Is it B?
no
huh
D + B = 180 - plug in the values of D and B
(2x 16) + x =180
yep
thanks
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