Question

1.The following unbalanced equation describes the reaction that can occur when lead (II) sulfide reacts with oxygen gas to produce lead (II) oxide and sulfur dioxide gas:
PbS + O2  PbO + SO2
Balance the equation and describe in words the electron transfer(s) that takes place?? Help

Answer 1

2PbS + 3O2  2PbO + 2SO2

It's a reduction, as the Oxygen pass from 0 (in O2) in to -2 (in PbO or S02), so it get electrons.