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OpenStudy (anonymous):
What is this TRIG identity called. see attachment.
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OpenStudy (anonymous):
OpenStudy (anonymous):
@dan815
OpenStudy (anonymous):
@LynFran
OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
I'm not sure if there is a specific name for this identity
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OpenStudy (anonymous):
how would I explain it though
jimthompson5910 (jim_thompson5910):
I guess you could say "composition of a trig function and another inverse" ? I'm not sure
jimthompson5910 (jim_thompson5910):
oh you want to know how they got that identity?
OpenStudy (anonymous):
yeah
OpenStudy (anonymous):
here let me give you an example
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jimthompson5910 (jim_thompson5910):
tan(arccos(x))
let theta = arccos(x)
so cos(theta) = x = x/1
agreed?
OpenStudy (anonymous):
\[\tan(\cos^-1(1/2)\]
OpenStudy (anonymous):
yes agreed
jimthompson5910 (jim_thompson5910):
so we can create this right triangle
|dw:1438215201249:dw|
jimthompson5910 (jim_thompson5910):
|dw:1438215224912:dw|
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jimthompson5910 (jim_thompson5910):
cos(theta) = x/1
cosine deals with adjacent over hypotenuse
jimthompson5910 (jim_thompson5910):
so we can add these labels
|dw:1438215259342:dw|
jimthompson5910 (jim_thompson5910):
what is the missing side equal to (in terms of x) ?
OpenStudy (anonymous):
1^2-x^2
jimthompson5910 (jim_thompson5910):
it will be the square root of that
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jimthompson5910 (jim_thompson5910):
|dw:1438215360088:dw|
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