Question

A punter kicks a football upward with an initial speed of 48 feet per second. After how many seconds does the ball hit the ground?

Use the formula h = rt − 16t2 where h represents height in feet and r represents the initial speed.

Answer 1

So it looks like this?
\[h = 48t-16t^2\]

Answer 2

yea

Answer 3

so now what?

Answer 4

Graph it

Answer 5

cant graph that

Answer 6

Your h is 36

Answer 7

so you need to le the height = 0

and then solve

0 = 48t - 16t^2 for t

this can be factored

Answer 8

Now try to put it into quadratic form like
\[48t-16t^2-36=0\]

Answer 9

Then factor this and you should get 2 values.

Answer 10

4(8t-9)

Answer 11

No...use quadratic equation

Answer 12

t=3,0

Answer 13

yes

Answer 14

thats the amswer?

Answer 15

so the answer is 3 seconds

Answer 16

thx

Answer 17

A company launches 4 new products. The market price, in dollars, of the 4 products after a different number of years, x, is shown in the following table:


Product Function Year 1
(dollars) Year 2
(dollars) Year 3
(dollars)
Product 1 f(x) = x3 1 8 27
Product 2 g(x) = x2 + 11 12 15 20
Product 3 h(x) = 4x 4 16 64
Product 4 j(x) = 4x + 8 12 16 20


Based on the data in the table, for which product does the price eventually exceed all others?
Product 1
Product 2
Product 3
Product 4

Answer 18

can u help with this

Answer 19

h(x) is this?
\[4x^4\]

Answer 20

k

Answer 21

If it is product 3 will exceed all other price, it's increasing exponentially

Answer 22

so c

Answer 23

yes

Answer 24

wait

Answer 25

It's product 1, product 3 is only 4x

Answer 26

kk

Answer 27

A ball is thrown upward from the top of a building. The function below shows the height of the ball in relation to sea level, f(t), in feet, at different times, t, in seconds:

f(t) = −16t2 + 48t + 100

The average rate of change of f(t) from t = 3 seconds to t = 5 seconds is _____feet per second.

Answer 28

\[\left[\begin{matrix}Product & Function & Year 1 & Year 2 & Year 3\\ 1 & f(x)=x^3 & 1 &8 &27 \\ 2 & g(x) = x^2+11 & 12 &15&20 \\ 3 & h(x) = 4x & 4&16& 64 \\4 &j(x)=4x+8 &12 &16 &20\end{matrix}\right]\]

Answer 29

that should seem clearer when i put it this way

Answer 30

Ok take the derivative of the function f(t)

Answer 31

I hope you know how to do that

Answer 32

can i just solve for t

Answer 33

no you can't solve for t because every value of t gives you something new, its a function

Answer 34

and you are finding the rate of change

Answer 35

This curve looks like this

Answer 36

so you are solving for the tangent line like this