how do I differentiate 4sqrt(u^2+u) ?
with respect to u?
WELCOME TO OPENSTUDY!
i will help ya :)
Oh yes, sorry. It says Differentiate f(u) I have not yet differentiated using roots yet
lol fu
ok so first:
\[\sqrt[4]{u^2+u}\]
so first of all do you know how to simplify the equation?
See this......
@Carissa15 you there?
yes, that makes sense so far
I thought that you add 1/2 to "remove" the root from the equation but then I get lost..
??
So you could then take the derivative of the simplified equation? I didn't know how to simplify and remove the \[\sqrt{u}\] from the equation
O....... sqrt=1/2, 4sqrt=4/2=2. Got it?
cool, thank you :-) much more sense
My pleasure.... Don't forget to add a medal and be a fan. And definitely ask more questions. Will try my best to help!
which would leave me with \[4u^2+2(2u+1)+4u\] as the derivative?
\[\sqrt[4]{u^2+u} \implies (u^2+u)^{1/4}\] \[\frac{ d }{ du } (u^2+u)^{1/4} = \frac{ 1 }{ 4 }(u^2+u)^{-3/4} \times \frac{ d }{ du }(u^2+u)\] notice we apply the chain rule.
So your derivative should be \[\frac{ 1 }{ 4 }(u^2+u)^{-3/4} (2u+1)\]
|dw:1438235581850:dw|
Join our real-time social learning platform and learn together with your friends!