A country's population in 1990 was 156 million. In 1996 it was 162 million. Estimate the population in 2016 using the exponential growth formula. Round your answer to the nearest million.

Question

anonymous · Answer

@saseal

anonymous · Answer

@aric200

anonymous · Answer

$$162 = 156(1+x)^{6}$$

anonymous · Answer

So you need to solve for x first

aric200 · Answer

I just checked this, It seems correct http://openstudy.com/study#/updates/5201dbfbe4b0ebbcb9c6b14d @wolf1728 The population increases156,000,000 to 162,000,000 over 6 years 156,000,000 * (1+r)^6 = 162,000,000 (1+r)^6 = 162,000,000 / 156,000,000 (1+r)^6 = 1.03846153846154 6 * log(1+r) = log(1.03846153846154) log(1+r) = 0.01639041618817 / 6 log(1+r) = 0.0027317360313616 1+r = 1.0063098786004 r = .0063098786004 Testing the value of r 156,000,000 * (1+ .0063098786004)^6 = 1996 population 156,000,000 * 1.03846153846154 = 162,000,000 1996 population r = .0063098786004 Plug r in to find pop in 2016.

anonymous · Answer

how do I solve for x

anonymous · Answer

$$\frac{ 162 }{ 156 } = (1+x)^6$$

anonymous · Answer

26?

anonymous · Answer

$$1.038461538 = (1+x)^6$$
$$1.038461538 - 1 =0.38461538$$
$$\sqrt[6]{0.038461538} = 0.0063$$

anonymous · Answer

could u plz just tell me the answer bc I don't get it

anonymous · Answer

183.717165048

anonymous · Answer

that's the answer?

anonymous · Answer

yup

anonymous · Answer

$$2016-1990=26$$
$$156(1+0.0063098786004)^{26} = 183.717165048$$

hwyl · Answer

stop giving out answers. cheating will not be tolerated

wolf1728 · Answer

To solve for x you need to tale logs of both sides
162/156=(1+x)^6

wolf1728 · Answer

TAKE logs

wolf1728 · Answer

I guess jherbo isn't here anymore