If measurements of a gas are 50L and 300 kilopascals and then the gas is measured a second time and found to be 75L, describe what had to happen to the pressure (if temperature remained constant). Include which law supports this observation.

Question

If measurements of a gas are 50L and 300 kilopascals and then the gas is measured a second time and found to be 75L, describe what had to happen to the pressure (if temperature remained constant).  Include which law supports this observation.

photon336 · Answer

pV = nRT   Do you know this law?

photon336 · Answer

The nR in that formula is the number of moles in our equation; we're not adding more gas so we can say that this is constant. 

so the formula becomes it's this way because (temperature number of moles are constant) so we take that out. 

$$P _{1}V _{_{1}} = P _{2}V _{2}$$

photon336 · Answer

Imagine you have two cylinders,  |dw:1438285455244:dw| one cylinder has the pressure and temperature of 50L and 300kPa  the other has a volume of 75L and an unknown pressure. 

Imagine that pressure = how many times the gas particles hit container. 
Volume = amount of space particles have to move 

if something has less space (less volume) the gas will be hitting the walls of the container more so pressure will be higher. 

if something has more space ( bigger volume) the gas will hit the walls of the container less so the pressure will be less. 

from that picture what would happen to the pressure and why?