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Solve the compound inequality 9 + 3n >= 6 or 5n < 25. a. n less than or greater to −1 or n < 5 b. n greater than or equal to −5 or n > 5 c. n greater than or equal to −1 or n < 5 d. n less than or greater to −5 or n > 5
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\(\bf{9+3n≥6~or~5n<25}\)
let's do the simple one first \(\bf{5n<25}\)
divide \(\dfrac{25}{5}\)
n< 5
correct b and c are out
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now \(\bf{9+3n≥6}\) subtract 6 - 9
3n ≥ -3
correct now divide \(\bf{\dfrac{-3}{3}}\)
-1
So it would be A?
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no the sign stays ≥ because you didn't divide by a negative so C
Ohhh
Thank you that makes more sense now
anytime ^_^
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