Question

...Easy Medal!!
Simplify 4 to the 7th over 5 squared all raised to the 3rd power.

4 to the 10th over 5 to the 5th

4 to the 4th over 5

4 to the 21st over 5 to the 6th

12 to the 7th over 15 squared

Answer 1

So is it like this? \[\large \sf \huge ( \large \frac{4^{7}}{5^{2}} \huge ) ^{3}\]

Answer 2

yes

Answer 3

@LegendarySadist

Answer 4

Then you would use the exponent rule: \[\large \sf (b^{n})^m~=~b^{n \times m}\]

Answer 5

which answer would that be

Answer 6

\[\large \sf (\frac{b^{n}}{a^{l}})^m~=~\frac{b^{n \times m}}{a^{l \times m}}\]

Answer 7

I don't get it

Answer 8

That's not good

Answer 9

..