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OpenStudy (anonymous):
How do you solve this? (Explain please)
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OpenStudy (anonymous):
\[\sum_{n=1}^{3}\frac{ 1 }{ n ^{3} }\]
OpenStudy (anonymous):
okay so basically in this problem you have to add the values of \[(1/1^3) + (1/2^3) + (1/3^3)\]
OpenStudy (anonymous):
you see that n =1 one at the bottom of the sigma
OpenStudy (anonymous):
that means you start with 1
OpenStudy (anonymous):
Oh does the three on the top mean you end with 3?
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OpenStudy (anonymous):
yes exactly, if it was say 6 you would keep adding the equations with variables up to 6
OpenStudy (anonymous):
if at the bottom it said n=3 you would start at three, its a rather hard concept to wrap your head around do you get it?
OpenStudy (anonymous):
Oh okay. So the answer would be 195/162?
OpenStudy (anonymous):
fun fact if instead of a \[\sum_{?}^{?} you see a \prod_{?}^{?} \it means multiply \]
OpenStudy (anonymous):
instead of add
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OpenStudy (anonymous):
dont know havent worked it out give me a sec
OpenStudy (anonymous):
Alright
OpenStudy (anonymous):
strange i got 251/216
OpenStudy (anonymous):
Did u add 1 + 1/6 + 1/27?
OpenStudy (lynfran):
thats correct @Jdosio
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OpenStudy (anonymous):
no you have to add 1+ 1/8 + 1/27
OpenStudy (anonymous):
Oh whoops! I messed up on that. Thanks!
OpenStudy (anonymous):
yep no problem :D
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