Question

A pitcher throws a baseball straight into the air with a velocity of 72 feet/sec. If acceleration due to gravity is −32 ft/sec2, how many seconds after it leaves the pitcher's hand will it take the ball to reach its highest point? Assume the position at time t = 0 is 0 feet.

Answer 1

use an equation for constant acceleration
u = initial velocity = 72 , a = -32, t = ? , v = final velocity = 0

v = u + at
0 = 72 - 32t

solve for t

Answer 2

2.25?

Answer 3

72 / 32 = 2.25

yes

Answer 4

thank you!

Answer 5

yw

Answer 6

i'm meeting so many people who dont say thanks today....

Answer 7

Its common courtesy to say thank you :p

Answer 8

especially for an answer

Answer 9

yes