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Mathematics 18 Online
OpenStudy (anonymous):

If h(x) = g[f(x)], use the table of values for f, g, f ′ and g ′ to find the value of h ′(1)

OpenStudy (anonymous):

x f(x) g(x) f ′(x) g ′(x) 1 3 2 2 6 2 1 8 5 7 3 7 2 7 9

OpenStudy (anonymous):

@LynFran @pooja195

OpenStudy (loser66):

First off, h'(x) =??

OpenStudy (anonymous):

i have no idea

OpenStudy (anonymous):

would the product rule apply?

OpenStudy (anonymous):

do i just derive g and f?

OpenStudy (loser66):

it's chain rule, not product rule

OpenStudy (anonymous):

okay so then it would be h'(x) = g'(f(x)) + g(f'(x))?

OpenStudy (anonymous):

or is it h'(x) = g'(f(x)) * f'(x)

OpenStudy (loser66):

the last one.

OpenStudy (loser66):

now replace all f'(1) =?

OpenStudy (loser66):

f(1) =??

OpenStudy (anonymous):

h'(x)= 2?

OpenStudy (anonymous):

correction h'(1) = 2

OpenStudy (loser66):

nope

OpenStudy (anonymous):

damn okay what'd i do wrong h'(x) = g"(3) * 2

OpenStudy (anonymous):

only one prime on the g ^^

OpenStudy (loser66):

=??

OpenStudy (anonymous):

18 damn okay i see what i did wrong

OpenStudy (loser66):

ok

OpenStudy (anonymous):

thank you very much

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