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If h(x) = g[f(x)], use the table of values for f, g, f ′ and g ′ to find the value of h ′(1)
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x f(x) g(x) f ′(x) g ′(x) 1 3 2 2 6 2 1 8 5 7 3 7 2 7 9
@LynFran @pooja195
First off, h'(x) =??
i have no idea
would the product rule apply?
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do i just derive g and f?
it's chain rule, not product rule
okay so then it would be h'(x) = g'(f(x)) + g(f'(x))?
or is it h'(x) = g'(f(x)) * f'(x)
the last one.
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now replace all f'(1) =?
f(1) =??
h'(x)= 2?
correction h'(1) = 2
nope
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damn okay what'd i do wrong h'(x) = g"(3) * 2
only one prime on the g ^^
=??
18 damn okay i see what i did wrong
ok
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thank you very much
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