help asap please i need given and prove for each box in order.
pleaseee
@ganeshie8
@dan815
@nincompoop
since AC is a bisector, then we can write: \[\Large \angle DAE \cong \angle BAE\]
\[\Large \angle AED \cong \angle AEB\] since they are right angles
side AE is a common side between triangles AEB and AED so triangles AED and AEB are similar for ASA criterion
sorry triangles AED and AEB are congruent each to other for ASA criterion, not similar finally, since AEB and AED are congruent triangles, then we have: \[\Large AD \cong AB\]
im lost :/
reassuming: step #1 since BD is a bisector, then we have: \[\Large \angle ABE \cong \angle ADE\]
step#2 we have: \[\angle AED \cong \angle AEB\] since they are both right angles
then since in a triangle the sum of interiuor angles is 180 degrees step#3 \[\Large \angle DAE \cong \angle BAE\]
interior*
am I right?
i have to fill in the blanks with those little answers from the buttom
I know, so you can fill with my step#1 and step#2
i am suppose to put 2 answer for each box.
step#4 triangle AEB and AED are congruent each other by ASA criterion, since: AE is a common side, and, as I wrote in step#3 \[\Large \angle DAE \cong \angle BAE\]
I'm pondering...
Join our real-time social learning platform and learn together with your friends!