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Mathematics 7 Online
OpenStudy (bia_gonzalex):

help asap please i need given and prove for each box in order.

OpenStudy (bia_gonzalex):

OpenStudy (bia_gonzalex):

pleaseee

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

@dan815

OpenStudy (anonymous):

@nincompoop

OpenStudy (michele_laino):

since AC is a bisector, then we can write: \[\Large \angle DAE \cong \angle BAE\]

OpenStudy (michele_laino):

\[\Large \angle AED \cong \angle AEB\] since they are right angles

OpenStudy (michele_laino):

side AE is a common side between triangles AEB and AED so triangles AED and AEB are similar for ASA criterion

OpenStudy (michele_laino):

sorry triangles AED and AEB are congruent each to other for ASA criterion, not similar finally, since AEB and AED are congruent triangles, then we have: \[\Large AD \cong AB\]

OpenStudy (bia_gonzalex):

im lost :/

OpenStudy (michele_laino):

reassuming: step #1 since BD is a bisector, then we have: \[\Large \angle ABE \cong \angle ADE\]

OpenStudy (michele_laino):

step#2 we have: \[\angle AED \cong \angle AEB\] since they are both right angles

OpenStudy (michele_laino):

then since in a triangle the sum of interiuor angles is 180 degrees step#3 \[\Large \angle DAE \cong \angle BAE\]

OpenStudy (michele_laino):

interior*

OpenStudy (michele_laino):

am I right?

OpenStudy (bia_gonzalex):

i have to fill in the blanks with those little answers from the buttom

OpenStudy (michele_laino):

I know, so you can fill with my step#1 and step#2

OpenStudy (bia_gonzalex):

i am suppose to put 2 answer for each box.

OpenStudy (michele_laino):

step#4 triangle AEB and AED are congruent each other by ASA criterion, since: AE is a common side, and, as I wrote in step#3 \[\Large \angle DAE \cong \angle BAE\]

OpenStudy (michele_laino):

I'm pondering...

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