If 10.0 mL of a 1.536 M solution of NaOH was poured into 24.0 mL of distilled water, the concentration of the resulting solution is __________ M.
!st u find the no. of moles of NaOH in 10ml. As we all know the no. of moles of NaOH won't change cuz we aren't adding or removing NaOH right? So the next step would be calculating the concentration by taking the no. of moles of NaOH and dividing it by the total volume after the addtion of the distilled water. ( since it is distilled water no reaction will occur ) So take the volume as 34ml and make t
\[N _{a}V _{a} = N _{b}V _{b}\] \[V _{1} = 10 mL \] \[V _{2} = (10.0mL + 24.0mL H _{2}O\]
I agree with Rushwr, find the number of moles of NaOH in a solution with that concentration. and then you can solve for the concentration of resulting solution
So the answer is 34?
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