Question

If sin θ = 1/4 and tan θ > 0, what is the value of cos θ?

Answer 1

A) negative square root of 15
B) square root of 15
C) square root of 15 over 4
D) negative square root of 15 over 4

Answer 2

I will give you a hint: \[\theta is \in the first quadrant. That means \between 0 and 90 degree.\]

Answer 3

and im lost

Answer 4

hhhha

Answer 5

Okey you know:
\[\cos^2\theta+\sin^2\theta=1\]

Answer 6

sure

Answer 7

\[\cos^2\theta+(\frac{ 1 }{ 4 })^2=1\]

Answer 8

Do you know how to solve the previus eauation!

Answer 9

nope

Answer 10

look i appreciate ur helping me but i just want the answer plz

Answer 11

You have to learn :)

Answer 12

\[\cos \theta=\sqrt{1-\frac{ 1 }{ 16 }}\]

Answer 13

insert it in the calc!

Answer 14

ok

Answer 15

0.96?

Answer 16

\[\frac{ \sqrt{15} }{ 4 }\]

Answer 17

i should learn to read
it says the SINE

Answer 18

adjacent sides is \(\sqrt{4^2-1^2}=\sqrt{15}\)

Answer 19

oh

Answer 20

so the cosine is \(\frac{\sqrt{15}}{4}\) same answer as the other way, just a different perspective