A juggler is performing her act using several balls. She throws the balls up at an initial height of 4 feet, with a speed of 15 feet per second. If the juggler doesn't catch one of the balls, about how long does it take the ball to hit the floor? Hint: Use H(t) = −16t2 + vt + s. 7.52 seconds 1.15 seconds 0.47 second 0.22 second
\[H(t)=-16t^2+15t+4\] set \[-16t^2+15t+4=0\] and solve for \(t\)
on account of when it hits the floor, the height is zero
you can solve by a) using the quadratic formula or b) cheating i prefer cheating http://www.wolframalpha.com/input/?i=-16t^2%2B15t%2B4%3D0
actually it is NOT D
beware of answers with no explanation they are often wrong and you have no way of knowing
Yeah I've learned my lesson from those :P I enjoy option b and wolframalpha as well :)
lol yeah B
That's what I was just about to say, it took me a while but I noticed it's close to 1.2 and the only answer close to that was 1.15
Funny how we chose option b and the answer ended up being b xD
I'm confused by that...
my bad i thought this was physics
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