pleas can anyone helm me prove that arbitrary intersection of open set is not open????
Are you working with topological spaces or metric spaces in this assignment? Basically, what is the definition of open set that you are to use?
metric space sir
OK. Thanks, that helps us know what to focus on.
After consulting my textbook, it seems that all you need is a counterexample to prove this.
Let A, B are open set then \(A\cup B\) is an open set also Suppose \(A\cap B \) is not empty consider compliment of \(A\cap B\) that is the set of element in A or in B and we know that that set is open, hence \(A\cap B\) is closed.
ok sir but what textbook do you thick should be the best to study metic space for a dummie like me ?
I like that @Loser66. Very elegant.
@Loser66 can you be specific using the real line R here sir , please
hey @jtvatsim now is your turn :)
because i get more confuse trying to understand my text book.
But sometimes the intersection of two open sets IS open. :) Consider (0,3) and (1,2). The intersection is (1,2) which is still open. It is arbitrary intersections that cause problems.
Anyways, to answer your question @GIL.ojei I have yet to find a good introduction to metric spaces. I've struggled with almost all textbooks on the subject. But, I did find this example for the real line.
I think that the arbitrary union of open sets is open
Consider the set of open intervals centered around the point 0. That is, the family (-1/i, 1/i). Then, consider the infinite intersection \[\cap_{i = 1}^\infty (-1/i, 1/i)\] You will see that as this proceeds to infinity the intervals converge to (0,0) or just the single point {0}. Since a single point is not open, we have shown that an arbitrary intersection of open intervals need not be open.
here is a link @Michele_Laino ,@jtvatsim and @Loser66 ,,, please hepl explain page 17 and 18(remark 1 and 2)
any help sirs?
Go to this page , read section 2.1. It is wayyyyyyyyyyy clearer than your text book https://books.google.com/books?id=mMBY5jdjGfoC&printsec=frontcover&source=gbs_ge_summary_r&cad=0#v=onepage&q&f=false
according to the observation of @jtvatsim if the result of an arbitrary intersection, for example an infinite intersection, is a one point set, then we can show that in a metric space, which is also a topological space, any one point set is a closed set
@Loser66 can't find a way to read the text book
oh, you are not in America. That's why you can't open that site. Am I right?
yes sir @Loser66
How about this? watch section 14 topology. https://www.youtube.com/watch?v=FHL4udeLf9Q&index=14&list=PLZzHxk_TPOStgPtqRZ6KzmkUQBQ8TSWVX
This one is different than Loser66's but I've heard good things about this one: http://www.topologywithouttears.net/topbook.pdf
ok hard that before but he did not explain matric space in dept
metric space is a set equipped with a function, called distance
ok thanks @Michele_Laino
thanks @Loser66 and thats @jtvatsim .. you guys have been helpful
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