Consider the following unbalanced redox reaction:

MnO4- + S2O32- → Mn2+ + SO42-

What is the reduction half-reaction?

MnO4- → SO42-

MnO4- → Mn2+

S2O32- → SO42-

S2O32- → Mn2+

Question

Consider the following unbalanced redox reaction:

MnO4-  +  S2O32-     →     Mn2+   +   SO42-

What is the reduction half-reaction?
		
MnO4-     →     SO42-
		
MnO4-     →     Mn2+
		
S2O32-     →     SO42-
		
S2O32-      →     Mn2+

taramgrant0543664 · Answer

Which one do you think it is?

taramgrant0543664 · Answer

We know that it is not A or D a half reaction shows the reaction for one element so it wouldn't chand it either needs to be Mn or S only it can't be Mn and S

taramgrant0543664 · Answer

We are looking for the reduction portion so reduction gains electrons, oxidation loses electrons

taramgrant0543664 · Answer

MnO4-   In order to get the -1 charge Mn has a charge of +7 and on the other side of the reaction Mn has a charge of +2 it is gaining electrons since it's getting closer to being negative so it is being reduced

taramgrant0543664 · Answer

Do you understand @ajeecutie ?

welshfella · Answer

yep