Question

Where is the first derivative of y = 3xe−x equal to 0?

Answer 1

okay so iv got the derivative
(-3e^(-x))(x-1)

Answer 2

So they gave you \[\Large y = 3xe^{-x}\] right?

Answer 3

yes

Answer 4

I'm getting \[\Large \frac{dy}{dx} = -3e^{-x}(x-1)\] as well

Answer 5

now set dy/dx equal to 0 and solve for x

Answer 6

yea well thats what i cant do

Answer 7

\[\Large \frac{dy}{dx} = -3e^{-x}(x-1)\]
\[\Large 0 = -3e^{-x}(x-1)\]
\[\Large -3e^{-x} = 0 \text{ or } x-1 = 0\]

Answer 8

I'm using the idea A*B = 0 means either A = 0 or B = 0

Answer 9

Does that make sense? @Jdosio

Answer 10

okay sorry just fell asleep in my desk yes iv got it thank you verry much:D