Question

help Please!!!

Answer 1

How do i create the data table to plot the velocity time graph?

Answer 2

@Michele_Laino

Answer 3

......for both the runner and the car?

Answer 4

the velocity of the car is v=cost=4 m/sec
whereas the velocity of the runner is v=a*t=0.5*t

Answer 5

ok what is "cost"?

Answer 6

"cost" stands for constant

Answer 7

ok but how do i make the data table to plot the points on the graph. and how did you know the graph looks like this????

Answer 8

since the function:
\[v = at\]
is represented by a line which passes at the origin, in the (t, v) plane

Answer 9

i mean how did you make the graph without
T(sec) Velocity m/sec
0 0
1 some number
2 some number

Answer 10

is the acceleration along of 20 seconds of time?

Answer 11

i don't know!!! :(

Answer 12

from your text I see that the runner accelerates for 20 seconds

Answer 13

yah....!!!

Answer 14

ok tell me how do i make the data table from velocity and average velocity???

Answer 15

ok so the graph of this function:
\[v\left( t \right) = at = 0.5t\]
passes at point t=0, v=0 and passes at point t=20, v=0.5*20=10

Answer 16

yes....!!!!

Answer 17

i got that....

Answer 18

how do i figure out how far the runner will be in 1,2,3,4,5,6,7,8,9,10,11,12,13,14-20 secods

Answer 19

whereas the velocity of the car is constant
the function
v=4, is represented by the subsequent line:

Answer 20

ok so that car will cover 4 meters every second...got that.

Answer 21

yes!

Answer 22

what about the runner tho :(

Answer 23

the space traveled by the runner, is given by the subsequent formula:
\[\Large s\left( t \right) = \frac{1}{2}a{t^2}\]

Answer 24

i want to make a proper data table for both the car and the runner and plot those point on to the graph so it looks pretty neat.

Answer 25

what does "s" stand for?

Answer 26

"s(t)" stands for space as function of time

Answer 27

never learned about that in physics.. so can i use that formula to figure out the velocity of the runner at any given time???

Answer 28

in order to make a table, you have to consider these times:
t=1
t=2
t=3
t=4
t=5
...
t=20
and compute the corresponding spaces, using this formula:
\[\Large s\left( t \right) = \frac{1}{2}a{t^2} = \frac{1}{2} \times 0.5{t^2} = \frac{{{t^2}}}{4}\]

Answer 29

that is the graph for runner.
In order to make a table for car, you have to consider the same times, namely:
=1
t=2
t=3
t=4
t=5
...
t=20
and then you have to compute the distance using the subsequent formula:
\[\Large s\left( t \right) = 4t\]

Answer 30

so what does s(t) = 4t means tho???

Answer 31

s(t)=4t, it is the space traveled by the car at time t

Answer 32

so 4 meters?

Answer 33

no, it is:
4*t where t is the time

Answer 34

for example, at t=2, we have:
\[s\left( 2 \right) = 4 \times 2 = 8\]

Answer 35

yah but at 1 second, the runner covered 4meters right since 4X1sec = 4m?????

Answer 36

the car travelled 4*1= 4 meters, whereas the runner travelled 1/4= 0.25 meters

Answer 37

ok so the example that you gave me a second ago was for whome, the runner or the car.....???? car?

Answer 38

ok let me try and i'll get back to you......Thank you and bless you!!! :)

Answer 39

more explanation:
\[\Large \begin{gathered}
spac{e_{car}} = 4 \times t \hfill \\
\hfill \\
spac{e_{runner}} = \frac{{{t^2}}}{4} \hfill \\
\end{gathered} \]

Answer 40

ok i got it...Thanks make gotta wite the formula down.... Peace :)

Answer 41

:)

Answer 42

:)

Answer 43

ok i didn't quite get this.....Space runner = t^2/4
because i'm not getting the same number here....