It takes 0.225 seconds/revolution for a body of mass of 25 grams to rotate a circle with a radius of 15 cm. What is the centripetal force acting on that body?
force = m w r^2 F is in Newtons . mass in kgs and r in meters w = the angular velocity in radians / sec you can work this out from the given speed in revs / sec.
how can I convert seconds/revolution to radians/sec?
1 rev = 2 pi radians it travels 2 pi radians in 0.225 secs so in 1 second it travels 2 pi / 0.225 radians
w = 8.89 pi rads/sec
5x10^(-3) ?
now you need to convert 25 gms to kgs and 15 cms to meters.
what is 5x10^-3 ?
the answer for the centripetal force?
hmm..
not quite - you need to multiply that by pi
sorry i forgot to put pi, is it 0.0157?
yes thats in newtons
you can write it as 1.57 * 10^-2 N
the answer is not in the choices :(
i know other formulas maybe we can try that :)
oh - maybe i've gone wrong somewhere - its been a while since i did these what are the choices?
\[T = 2\pi(r) \over v\]
0.731 N, 749.47 N, 187.368 dynes, 2,924 N
Isn't centripetal force \[\sf F_c = \frac{ mv^2}{r}\]
yes where v = linear velocity
yes @Jhannybean :)
since centripetal acceleration = \(\sf a_c = \dfrac{v^2}{r}\)
cool, I still remember \(\checkmark\) haha
yea my memory has failed me here I should have checked
i was too confident lol!
\[T = \frac{ (2\pi(r)) }{ v }\]
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