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Mathematics 7 Online
OpenStudy (anonymous):

How would I solve this?

OpenStudy (anonymous):

OpenStudy (jhannybean):

\[\large \frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2} \longrightarrow \frac{(x-(-4))^2}{3^2} -\frac{(y-(-3))^2}{4^2}=1\]

OpenStudy (jhannybean):

On the left you have the equation of a hyperbola, and the right arrow is what the equation of the hyperbola translates into, which is your function

OpenStudy (jhannybean):

To find the foci and vertices, we need to identify what the center is. center : \((h,k)\)

OpenStudy (anonymous):

That's wrong, sorry.

OpenStudy (anonymous):

hmm

OpenStudy (jhannybean):

?...

OpenStudy (anonymous):

-4,-3

OpenStudy (jhannybean):

Good.

OpenStudy (jhannybean):

Now the foci lie along the horizontal transverse axis, what you know as the major axis. Therefore to find their location, we use the formula \[(h+c),k ~,~ (h-c),k~~, c^2=a^2+b^2 \longrightarrow c=\sqrt{a^2+b^2}\]

OpenStudy (anonymous):

c=5

OpenStudy (anonymous):

(1, -3,) (-9,-3)

OpenStudy (jhannybean):

To find the vertices, you use the equation \[{(h+a),k} ~,~ {(h-a),k}\]

OpenStudy (anonymous):

(-1, -3) (-7,-3)

OpenStudy (anonymous):

?

OpenStudy (jhannybean):

Yes, c = 5. You are right.

OpenStudy (anonymous):

Thank you, could you help me with one more?

OpenStudy (jhannybean):

Sure, i can try

OpenStudy (anonymous):

Thanks :) This is like the opposite I guess.

OpenStudy (anonymous):

@Jhannybean

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