Simplify the rational expression please help and explain with me?√125h^4 choices a.5h^2√5 b.25h^2√5 c.h√62.5 d.5√5h^4
I have a idea what to do but the power of 4 makes me get lost,
look at the problem this way \[\sqrt{5 \times 25 \times h^2 \times h^2}\] which terms can you take the square root of..?
25 would be 5 and wouldn't h^2 and h^2 be crossed out? still new to this
well 25 to 5 is correct h^2 goes to h when you take the square root so the problem can be rewritten as \[\sqrt{5} \times \sqrt{25} \times \sqrt{h^2} \times \sqrt{h^2} = \sqrt{5} \times 5 \times h \times h\] just simplify it
you get the same as you had before= right?if to solve it
well it has been simplified now... all you need to do is tidy up the answer so it matches one of your choices
and how would you go about doing this?
ok... in bits \[\sqrt{5} \times 5 = 5 \sqrt{5}\] what does \[h \times h =\]
25 and h^2?
h^2 is correct so its now \[5 \times \sqrt{5} \times h^2 = 5 \times h^2 \times \sqrt{5}\] rememeber when muliplying, the order doesn't matter
can you square root 5 though is that even possible?
ok... the solution in correct but in algebra will normally don't write the multiplication signs when writing a term... so how can you rewrite \[5 \times h^2 \times \sqrt{5}\]
so wouldn't the answer be 5h^2√5?
just write it without the multiplication signs
that's correct
\( \sqrt{5} \) is theoretically possible... but it is not a "nice" number 2.236067977499789696409173668731276235440618359611525724270897245410520925637804899414414408378782275... it goes on forever (ugh!)
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