A newly discovered planet has a mass 1.5 times compared to that of the earth, and its diameter is 3 times compared to earth. What is the gravitational acceleration on this planet?
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OpenStudy (welshfella):
now this is a formula i have definitely forgotten
OpenStudy (anonymous):
Fg = Gm1m2/r^2
OpenStudy (anonymous):
or Fg = Gm/r^2
OpenStudy (welshfella):
oh ok
so n1 amd m2 are the masses and r^2 = radius?
OpenStudy (anonymous):
yes ;)
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OpenStudy (welshfella):
G is the acceleration due to gravity?
OpenStudy (anonymous):
G = 6.67 X10^-11
OpenStudy (anonymous):
yes :)
OpenStudy (welshfella):
I'm not entirely clear about it and i haven't the time to look it up . sorry
OpenStudy (anonymous):
oh it's okay thank you :)
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\[mg=G \frac{Mm}{r^2}\]
\[g=G \frac{M}{r^2}\]\[g \alpha \frac{M}{r^2}\]
\[\frac{g'}{g}=\frac{\frac{M'}{r'^{2}}}{\frac{M}{r^2}}\]\[g'=g \frac{M'r^{2}}{Mr'^{2}}\]
M'=Mars of new planet
r'=radius of new planet
M=mass of earth
r=radius of earth
Also given
\[M'=1.5M\]
for the radius also u can calculate