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Chemistry 8 Online
OpenStudy (superhelp101):

Question:

OpenStudy (superhelp101):

When an atom releases a beta particle, the mass number decreases by one. the mass number increases by one. the atomic number increases by one. the atomic number remains the same.

OpenStudy (superhelp101):

@JFraser

OpenStudy (jfraser):

what is the isotopic symbol for a beta particle?

OpenStudy (superhelp101):

|dw:1438469062312:dw|

OpenStudy (superhelp101):

isn't it?

OpenStudy (jfraser):

that's the one

OpenStudy (jfraser):

now suppose an atom of carbon-14 undergoes beta decay

OpenStudy (jfraser):

\[^{14}_{6}C \rightarrow ^0_{-1} \beta + ^A_Z?\]

OpenStudy (jfraser):

in nuclear reactions, the \(total\) atomic number must be conserved, and the \(total\) mass number must also be conserved

OpenStudy (superhelp101):

oh okay

OpenStudy (jfraser):

since the total atomic number \(must\) add up to 6, what must the other particle be to make the bottom "equation" true?

OpenStudy (superhelp101):

7?

OpenStudy (jfraser):

since those are atomic numbers, what particle has an atomic number of 7?

OpenStudy (superhelp101):

nitrogen

OpenStudy (jfraser):

and what about the mass number?

OpenStudy (superhelp101):

nitrogen atomic mass 14.00674

OpenStudy (superhelp101):

litium

OpenStudy (jfraser):

you don't need the average mass of nitrogen, look at the mass numbers from the equation. What do they have to equal?

OpenStudy (superhelp101):

6

OpenStudy (jfraser):

masses, not atomic numbers

OpenStudy (superhelp101):

14

OpenStudy (jfraser):

very good

OpenStudy (jfraser):

so the whole equation will look like: \[\large{^{14}_{6}C \rightarrow \space ^{0}_{-1} \beta + \space ^{A}_{7}N}\]

OpenStudy (superhelp101):

yes

OpenStudy (jfraser):

\[\large{^{14}_{6}C \rightarrow \space ^{0}_{-1} \beta + \space ^{14}_{7}N}\]

OpenStudy (jfraser):

so now that you have a completed beta decay equation, you can answer the question

OpenStudy (superhelp101):

C?

OpenStudy (jfraser):

the atomic number goes from 6 to 7, so it must increase by one

OpenStudy (jfraser):

good job

OpenStudy (superhelp101):

thx

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