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OpenStudy (superhelp101):
When an atom releases a beta particle,
the mass number decreases by one.
the mass number increases by one.
the atomic number increases by one.
the atomic number remains the same.
OpenStudy (superhelp101):
@JFraser
OpenStudy (jfraser):
what is the isotopic symbol for a beta particle?
OpenStudy (superhelp101):
|dw:1438469062312:dw|
OpenStudy (superhelp101):
isn't it?
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OpenStudy (jfraser):
that's the one
OpenStudy (jfraser):
now suppose an atom of carbon-14 undergoes beta decay
OpenStudy (jfraser):
\[^{14}_{6}C \rightarrow ^0_{-1} \beta + ^A_Z?\]
OpenStudy (jfraser):
in nuclear reactions, the \(total\) atomic number must be conserved, and the \(total\) mass number must also be conserved
OpenStudy (superhelp101):
oh okay
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OpenStudy (jfraser):
since the total atomic number \(must\) add up to 6, what must the other particle be to make the bottom "equation" true?
OpenStudy (superhelp101):
7?
OpenStudy (jfraser):
since those are atomic numbers, what particle has an atomic number of 7?
OpenStudy (superhelp101):
nitrogen
OpenStudy (jfraser):
and what about the mass number?
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OpenStudy (superhelp101):
nitrogen atomic mass 14.00674
OpenStudy (superhelp101):
litium
OpenStudy (jfraser):
you don't need the average mass of nitrogen, look at the mass numbers from the equation. What do they have to equal?
OpenStudy (superhelp101):
6
OpenStudy (jfraser):
masses, not atomic numbers
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OpenStudy (superhelp101):
14
OpenStudy (jfraser):
very good
OpenStudy (jfraser):
so the whole equation will look like:
\[\large{^{14}_{6}C \rightarrow \space ^{0}_{-1} \beta + \space ^{A}_{7}N}\]