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Find the indicated function values for the following function f(x)5x-2 ----- x-5 a.) f(0) b.) f(1) c.) f(-5) d. f( a+b ) e. why must 5 be excluded from the domain of?
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\[f(x)=\frac{5x-2}{x-5}\]
Is that what you meant?
so our function is \[f(x)=\frac{ 5x-2 }{ x-5 }\]and we want to know what f(0).. so where ever we see "x" in the give function we substitute '0' so..\[f(0)=\frac{ 5(0)-2 }{ (0)-5 }\]and we simplify it to get \[f(0)=\frac{ -2 }{ -5 }\]\[f(0)=\frac{ 2 }{ 5 }\]...can u do the rest??
u just have to follow the same procedure as above
what u got for f(1) ...??
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\[f(1)=\frac{ 5(1)-2 }{ (1)-5 }\]
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