someone please check my work......Thanks

Question

yumyum247 · Answer

attachment

yumyum247 · Answer

@oldrin.bataku

yumyum247 · Answer

@nincompoop please cheque my work....:)

yumyum247 · Answer

does my work make any sense to you????????o_O

nincompoop · Answer

sure

yumyum247 · Answer

that's such a political response but i'll take that as a yes!!!

yumyum247 · Answer

Thank you :)

nincompoop · Answer

https://www.youtube.com/watch?v=d-_eqgj5-K8

astrophysics · Answer

I think nincompoop's profile picture matches your question and it's tilting it's head to read what you wrote :P

yumyum247 · Answer

attachment

yumyum247 · Answer

@IrishBoy123 please help

yumyum247 · Answer

i;ve already done the question but the answer is different

yumyum247 · Answer

what have i done wrong??????

imqwerty · Answer

well the car is deaccelerating so u need to take the acceleration as -2.3m/s^2 :)

yumyum247 · Answer

ok let me try the question that way and i;ll get back to you

imqwerty · Answer

ok :)

imqwerty · Answer

try to think this way -
if the car ws accelerating instead of deaccelerating then it wuld have certainly covered more distance. 
so if u try to calculate the distance covered by the accelerating car u wuld apply this formula- S=ut +1/2 at^2
but u r applying the same formula for deaccelrating car so u r getting the same distance nd this is not possible so u can conclude that u made a mistake while taking the sign of acceleration :)

yumyum247 · Answer

got it......i got the answer Thanks man :)

yumyum247 · Answer

@Astrophysics LOL my question was pretty easy, maybe she has a sprained neck or something.

astrophysics · Answer

Haha, yes, kinematics problems aren't too difficult, the problem most people have with this is, the terms, and knowing what they mean. it can get confusing I guess, when you're dealing with average velocity, instantaneous velocity, displacement, distance, deceleration, etc =P

astrophysics · Answer

So for now you can think of deceleration as negative acceleration

astrophysics · Answer

deceleration = - a

yumyum247 · Answer

got it...actually i've this this unit before but yah i guess i forgot about this particular thing LOL :D

astrophysics · Answer

Haha, yeah but if you want to be technical, deceleration really just means decrease in speed, I really don't like this term though xD.

yumyum247 · Answer

me neither....!!! XD