Question

Another question:

Going to post them in a bit.

Answer 1

Will post soon. Going to be on the rate constant, and kinetics.

Answer 2

Posted here other one got cut off

Answer 3

Some more here

Answer 4

=D

Answer 5

Ok I think this is the last one for this question

Answer 6

I know this is a lot but some of them aren't that bad.

Answer 7

@Rushwr @taramgrant0543664

Answer 8

Ill start with the easy one 276. Im pretty sure OH is a intermediate

Answer 9

276. it's gotta be an intermediate because if it were a catalyist it would be generated in the last step again and unchanged. (Promoter and activator make no sense)

Answer 10

For 275 I'm not sure but I think that the concentration of CaCl2 would have no affect on the rate because it is a product and it isnt affecting the forward reaction. Not sure if my reasoning on this is sound though.

Answer 11

My answer also came down to that for 275 B,C, and D. would change the rate of the reaction.

Answer 12

Yea actually im certain for 275 that A would be the only answer that would not affect the reaction rate.

Answer 13

Yeah, sounds right to me, I guess the concentration of \(CaCl_2\) would only affect the equilibrium constant.

Answer 14

wait... I don't know for some reason I can't really decide between A and B

Answer 15

289. which one is false?

A. Chlorine goes from an oxidation state of 0 to -1 so it's reduced so that's true
B. increasing the temperature generally does increase the rate of reaction. \[k = Ae ^{Ea/Rt}\] you increase temperature i think the quantitiy Ea/Rt goes down i believe and k goes up and reaction rate goes up as well.
D yes HCL is a strong acid, and HCLO is a weak acid so that's true.

Answer 16

289 I think is C.

Answer 17

289. is C. here's my justification

Answer 18

The only thing that affect the equilibrium constant is temperature from what I remember.

Answer 19

Yeah it shouldn't affect the equilibrium constant, I guess the rate constant is not affected by concentrations of the products only concentration of reactants.

Answer 20

Like i thought it was C for 289 b/c

I notice that the number of moles of each quantity are the same. To me like an increase in pressure favors the side with fewer number of moles i think , while a decrease in pressure favors the side with more moles.. Keq

Answer 21

yeah it's only affected by temperature as well

Answer 22

sorry.. i was thinking in terms of what would favor the products.

Answer 23

My answer choice for 290 is B.

Answer 24

Okay so

276 D. "An OH radical is formed in the rate determining step but is consumed in the next step therefore it's an intermediate"

289 C The equilibrium constant is not affected by changes in concentrations and pressures remember that equilibrium states are separate from kinetic studies.

Answer 25

Looks good.

Answer 26

Yeah for 289 I don't think partial pressures come into play because we're only talking about liquids.

Answer 27

290. \[k[cl _{2}]^{0.5}[H _{2}O]\]

Answer 28

IF you look at the slow step the rate for formation depends on the formation of the chlorine radical and it's ability to react with water as well.