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OpenStudy (anonymous):
Which of the following expressions is the conjugate of a complex number with 2 as the real part and 3i as the imaginary part?
@primeralph
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OpenStudy (anonymous):
anyone ?
OpenStudy (irishboy123):
for the conjugate of : \(z = 2 + 3i \)
if \(z = a + i \ b\), then its conjugate \(\bar z\) or \(z^* = a - i \ b\)
OpenStudy (anonymous):
how do i set it up ?
OpenStudy (irishboy123):
you have \(z=2+3i \\\ = a+i b\)
you now want \(\bar z\) or \(z^* = a-i b \)
OpenStudy (irishboy123):
so a =
and
b =
and thus you have the conjugate
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OpenStudy (anonymous):
im thinking its 3i + 2. am i right
OpenStudy (irishboy123):
go back a step
if
\(z=2+3i =a+i \ b\), what is a and what is b ... ?
OpenStudy (irishboy123):
which is
\(z^∗=a−i \ b\)
OpenStudy (anonymous):
oh so 2+3i?
OpenStudy (irishboy123):
that's the number you started with
you are looking for its conjugate
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OpenStudy (anonymous):
totally confused
OpenStudy (irishboy123):
you started with
\(z=2+3i\)
you want its conjugate
you get there by simply reversing the sign of the imaginary part
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