Question

A car tire rotates 12.7 rev in 34 s. What is the angular velocity of the tire?

Answer 1

\(\large \omega = \frac{2 \pi}{T}\)

Answer 2

the frequency of rotation , f , is 12.7/34 (Hz). That's the number of revolutions per second.
This gives us information about the Time period of rotation , T.
T = 2π/w , (where w = angular velocity.)

from this we can deduce that w= 2π/T = 2πf. ( because f=1/T )
all that is left is to plug in the numbers: w = 2π (12.7/34) = 2.35 radians/second

Ans: 2.35 radians/second

Answer 3

U should not give the answer @AlexandruGuja