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How many grams of pure NaOH must be used to prepare 10.0 L of a solution that has a pH of 13?
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First step is to determine the concentration to do this you use the formula pH=-log[H+] 13=-log[H+] 10^-13=[H+] That'll give you the concentration of H+ ions
Now you have to find the mass of NaOH to do this you have to use the formula m=cv m is mass which is your unknown c is the concentration which you found in the previous step v is the volume which is the 10L
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