Question

if x^2 = 2x + 6 ... i need to solve for x.

Answer 1

=>X^2-2x-6=0

Answer 2

You can use the Quadratic Formula to find the values of x

Answer 3

a ,b , c values are \[\huge\rm Ax^2+Bx+C=0\]
where
a =leading coefficient
b= leading coefficient
c= constant term
\[\huge~\rm~x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]

Answer 4

http://www.purplemath.com/modules/quadform.htm

Answer 5

(x^2-2x+1)=6+1
(x-1)^2=7
now you can solve it.

Answer 6

then use quadratic formula

Answer 7

\[x^2 -2x -6 = 0 \] is in the form of \[ax^2 + bx + c = 0\]

where a = 1, b = -2, and c = -6

Answer 8

Simply plug those numbers into the Quadratic Formula

Answer 9

i think im maybe misunderstanding what im supposed to do?
the problem is
if x^2= 2x +6
then x can equal
(A) 2 - the square root of 28
(B) 1 - the square root of 28
(C) 1 - 2 root 7
(D) 1 - root 7
and none of the above..
i do have to solve for x right? i feel like im missing something