Question

2) 2/5x^2 -x+ 19/15 =0

Answer 1

lol

Answer 2

anyways lets see how i can help

Answer 3

is the first 2 part of the equation or no?

Answer 4

\[\frac{ 2 }{ 5 }x^2-x+\frac{ 19 }{ 15 }=0\]

Answer 5

I hope that makes it better

Answer 6

Much better ^-^

Answer 7

So I know
A= 2/5
B= -1
C= 19/15

Answer 8

Decimal answer correct?

Answer 9

yes

Answer 10

and Solving for x?

Answer 11

x = 1.455485

Answer 12

it says
"Use the quadratic formula to solve the equation."

"A. The solution set is ____"
(simplify your answer. type an exact answer, ysing radicals as needed. Use intefers or fractions for any numbers in the expression. Use a comma to separate answers as needed.)

"B. the solution is (emptyset)"

Answer 13

~eats pizza while waiting~

Answer 14

lol my b

Answer 15

~passes skittles~

Answer 16

omg. skittles with coffee

Answer 17

yes

Answer 18

^

Answer 19

Oh quadratic thought it was a normal equation sorry

Answer 20

lol, the only unit i have left is quadratic and I haven't done it in 2 years

Answer 21

hmm idk it's not giving me an answer

Answer 22

okay it's okay, let's move on to the next question?

Answer 23

sure

Answer 24

.6x^2 = 1.2x+0.6

Answer 25

\[0.6x^2-1.2x-0.6=0\]

Answer 26

wait is it an addition problem or subtraction?

Answer 27

I just flipped it so it's in standard form. it's still quadratic. just now it's all on one side.

Answer 28

...

Answer 29

Open this attachment up, It should help ^-^

Answer 30

what site did you use?

Answer 31

HI!!

Answer 32

. - . . _ .

Answer 33

\[\frac{ 2 }{ 5 }x^2-x+\frac{ 19 }{ 15 }=0\] is annoying
multiply by 15 and get
\[6x^2-15x+19=0\] then it will be much easier

Answer 34

you can use the quadratic formula or if you are a factoring wiz you can try that

Answer 35

yeah. I'm on here, asking for help. I'm not a factoring wiz.

Answer 36

ok well is it really
\[\frac{ 2 }{ 5 }x^2-x+\frac{ 19 }{ 15 }=0\]?

Answer 37

because that equation has no real solutions, maybe there is a typo there

Answer 38

yes. that's how it's written on my problem

Answer 39

well one of the answers is there is no solution

Answer 40

then either you are supposed to come up with two ugly complex solutions, or say "no solution"

Answer 41

so you sorta answered my question

Answer 42

ok fine
in any case you really want to multiply by 15 first and start with
\[6x^2-15x+19=0\] then, when you use the quadratic formula, you will see that there is no answer

Answer 43

you do not want to use decimals
you do not want to use fractions
you want to work with integers only

Answer 44

okay, thank you