What is the volume of 1.9 moles of chlorine gas (Cl2) at 298 K and 1.3 atm?
12 L
28 L
36 L
81 L
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OpenStudy (anonymous):
@pooja195
OpenStudy (anonymous):
@taramgrant0543664
OpenStudy (taramgrant0543664):
PV=nRT
P is pressure so 1.3 atm
V is the volume you are solving for
n is the moles of chlorine gas so 1.9 moles
R is your ideal gas constant (0.0821)
T is your temperature so 298K
So you can rearrange the formula to be
V=nRT/P
Solve for V
OpenStudy (anonymous):
so it would be c?
OpenStudy (taramgrant0543664):
Yes it would be!!
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OpenStudy (anonymous):
thanks ! can you Answer another one ?
OpenStudy (taramgrant0543664):
I can do one quick one but then I need to leave
OpenStudy (anonymous):
A container with a volume of 3.46 liters contains a gas at a pressure of 1.30 atmospheres and a temperature of 274.27 Kelvins. How many moles of gas are in the container?
0.1998 moles
0.5684 moles
4.891 moles
5.615 moles
OpenStudy (anonymous):
ok
OpenStudy (taramgrant0543664):
So same sort of thing as above using PV=nRT
This time you can rearrange it to be n=PV/RT
P would be 1.3atm
V would be 3.46L
R would still be 0.0821
T would be 274.27K
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