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OpenStudy (anonymous):

What is the volume of 1.9 moles of chlorine gas (Cl2) at 298 K and 1.3 atm? 12 L 28 L 36 L 81 L

OpenStudy (anonymous):

@pooja195

OpenStudy (anonymous):

@taramgrant0543664

OpenStudy (taramgrant0543664):

PV=nRT P is pressure so 1.3 atm V is the volume you are solving for n is the moles of chlorine gas so 1.9 moles R is your ideal gas constant (0.0821) T is your temperature so 298K So you can rearrange the formula to be V=nRT/P Solve for V

OpenStudy (anonymous):

so it would be c?

OpenStudy (taramgrant0543664):

Yes it would be!!

OpenStudy (anonymous):

thanks ! can you Answer another one ?

OpenStudy (taramgrant0543664):

I can do one quick one but then I need to leave

OpenStudy (anonymous):

A container with a volume of 3.46 liters contains a gas at a pressure of 1.30 atmospheres and a temperature of 274.27 Kelvins. How many moles of gas are in the container? 0.1998 moles 0.5684 moles 4.891 moles 5.615 moles

OpenStudy (anonymous):

ok

OpenStudy (taramgrant0543664):

So same sort of thing as above using PV=nRT This time you can rearrange it to be n=PV/RT P would be 1.3atm V would be 3.46L R would still be 0.0821 T would be 274.27K

OpenStudy (anonymous):

so b?

OpenStudy (anonymous):

or a? @taramgrant0543664

OpenStudy (taramgrant0543664):

I got a

OpenStudy (anonymous):

thanks!

OpenStudy (taramgrant0543664):

No problem!!

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