Question

If f(x)= (x^2)/2 (lnx)-(3/4) x^2 + C and f(1)=6, then find the values of C.

Answer 1

replace x with 1

Answer 2

then replace f(1) with 6

Answer 3

\[f(1)=\frac{1^2}{2} \ln(1)-\frac{3}{4}(1)^2+C \\ 6=\frac{1^2}{2} \ln(1)-\frac{3}{4} (1)^2+C\]

Answer 4

simplify a bit
and then solve for C

Answer 5

I came down to (1/2) ln - (3/4) + C

Answer 6

ln(1) is 0

Answer 7

do you know how to solve
6=-3/4+C
for C?

Answer 8

Oh. So would C=27/4?

Answer 9

yes

Answer 10

Oh. Okay. Thank You!

Answer 11

np