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Mathematics 17 Online
OpenStudy (anonymous):

What is the equation of the following graph?

OpenStudy (anonymous):

OpenStudy (mathstudent55):

Equation of a circle with radius r, and center at (h, k). \((x - h)^2 + (y - k)^2 = r^2\)

OpenStudy (mathstudent55):

Start by finding two things: 1. What is the radius of the circle? 2. What are the coordinates of the center of the circle?

OpenStudy (mathstudent55):

@biddyB Are you there?

OpenStudy (anonymous):

Sorry I was actually wrong! mathstudent55 is right. Sorry for the confusion!

OpenStudy (anonymous):

Ok, whew, I was really confused for a second. Thats ok, I get it now, thanks

OpenStudy (anonymous):

How do I find the radius?

OpenStudy (mathstudent55):

First, find the center.

OpenStudy (anonymous):

0?

OpenStudy (mathstudent55):

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OpenStudy (mathstudent55):

I think you got the right idea, but the center is actually (0, 0) since it's a point. It needs to have an x-coordinate and a y-coordinate.

OpenStudy (mathstudent55):

Now that you know where the center is, the radius is the distance from the center point to any point on the circle.

OpenStudy (mathstudent55):

It's easier if you measure along a horizontal or a vertical line.

OpenStudy (mathstudent55):

|dw:1438645313174:dw|

OpenStudy (anonymous):

3?

OpenStudy (mathstudent55):

Correct. The radius is 3. That means r = 3 The center of the circle is (0, 0). That means h = 0, and k = 0. Now we use these values in the equation above.

OpenStudy (mathstudent55):

\((x - h)^2 + (y - k)^2 = r^2\) \((x - 0)^2 + (y - 0)^2 = 3^2\) You see the substitutions of 0 for h, 0 for k, and 3 for r?

OpenStudy (mathstudent55):

Now we just simplify to: \(\large x^2 + y^2 = 9\) That is the answer.

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