Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (anonymous):

4 questions help please

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

@ganeshie8

hero (hero):

@dom4958, what are your thoughts regarding this problem? Are you familiar with the rate of change formula?

OpenStudy (anonymous):

not too much @Hero

hero (hero):

The average rate of change of a function \(f(x)\) over an interval between two points \((a, f(a))\) and \((b, f(b))\) is the slope of the secant line connecting the two points: \(\dfrac{f(b) - f(a)}{b - a}\) In this case, \(a = 3\) and \(b = 9\). What you want to do is find \(f(3)\) and \(f(9)\), then plug all the values in to the formula and simplify the expression which will give the average rate of change for this problem.

OpenStudy (anonymous):

f(6) over 6?

OpenStudy (anonymous):

2 over 2 @Hero ?

OpenStudy (anonymous):

@ganeshie8 @Hero

hero (hero):

Just a sec

OpenStudy (anonymous):

alright

hero (hero):

|dw:1438671186805:dw|

hero (hero):

If you notice the values along the \(y\) axis represent \(f(x)\) values because for functions \(y = f(x)\). In this case, \(f(3) \approx 47.25\) and \(f(9) \approx 27\).

hero (hero):

\(f(3) \approx 41.25\)

OpenStudy (anonymous):

@Hero what would i do with the f(3)≈41.25?

hero (hero):

Start with the formula for average rate of change: \(\dfrac{f(b) - f(a)}{b - a}\). We already acknowledged that \(a = 3\) and \(b = 9\)so plug in those values in place of \(a\) and \(b\): \(\dfrac{f(9) - f(3)}{9 - 3}\). Next plug in the appropriate values for \(f(3)\) and \(f(9)\), then simplify.

OpenStudy (anonymous):

-24.75 - 45.25 = 70 over 70. 7 over 7?

hero (hero):

Make sure you have the numbers written correctly. For example 9 - 3 = 6 and f(3) = 41.25

hero (hero):

Also, -a -b = -c.

OpenStudy (anonymous):

whats wrong with the ones i wrote isn't that correct? -24.75 - 45.25 = f(70)= f(7) -24.75 - 45.25 = 70= 7

OpenStudy (anonymous):

@Hero

hero (hero):

Put it this way, there's a reason why I made the suggestions I made.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!