Question

PLEASE HELP! A solution is made by dissolving 15.5 grams of glucose (C6H12O6) in 245 grams of water. What is the freezing-point depression of the solvent if the freezing point constant is -1.86 °C/m? Show all of the work needed to solve this problem.

Answer 1

@abb0t

Answer 2

@sweetburger @peachpi @mathway

Answer 3

so you need to find the molality which from what i remember is moles of solute/ kg of solvent

Answer 4

ΔT=-(Kf)m

Answer 5

@sweetburger I got 735.33

Answer 6

"m" it is not mass, it is represent molality or moles of solute per kg of solvent, you have to calculate the molality of the solution to calculate the delta T. The delta T is the difference between the freezing point of the pure solvent and the freezing point of the solution. Then the T freezing point of the pure solvent in this case water I think you may know the value or you can find it in the internet. knowing that and the delta T you can calculate the freezing point of the solution.