Question

A line passes through point (3, 7) and has a slope of 3/4

Answer 1

@DaBest21 @harryhart

Answer 2

in what form?

Answer 3

y=mx+b slope y-ntercept

Answer 4

Let the required line be y = mx+c in the slope intercept form, where m is the slope and c is the y intercept.

We determine m and c by the using given conditions.

m = 3/4, given.

So y = (3/4)x+c (1).

The line at (1) has the point (-8, 4) on it.

Therefore 4 = (3/4)*(-8)+c...(2)

(1)-(2) gives: y-4 = (3/4)(x+8).

=> y -4 = (3/4)x + 6

We multiply 4 to get integral coefficients.

4(y-4) = 3x+24

We rearrange.

3x-4y+24+16= 0

3x-4y+40 = 0 is the required line.

Answer 5

the options are- y=3/4x+19/4 and y=3x-19

Answer 6

what do you think it would be the answer?

Answer 7

y=3/4x+19/4

Answer 8

but im not sure

Answer 9

An easier approach for me atlest is this way:
\[\huge y-y_1=m(x-x_1)\]
where
m=slope
(x1,y1)
(3, 7) and has a slope of 3/4
y-7=3/4(x-3)
from here after you distribute and solve for y you get
y=3/4x+19/4

Answer 10

So what you said is correct

Answer 11

sweet

Answer 12

If point A(x, 5) lies on the line, the value of x is 33 or 1/3

Answer 13

still need help @harryhart

Answer 14

@DaBest21

Answer 15

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