Question

Use the Rational Zeros Theorem to write a list of all possible rational zeros of the function.

f(x) = -2x^4 + 4x^3 + 3x^2 + 18

Answer 1

Lol do you need help with this one ?

Answer 2

please
!!!!!!!!!

Answer 3

what are the factors of the leading coefficient? what are the factors of the constant term?

Answer 4

Similar problem as an example ;

f(x) = -2x^3 + 3x^2 -2x +8
Solution: Factors of the constant term (8) / Factors of the leading coefficient (-2)
so that would be: 1, 2, 4, 8 / 1, 2

So then each numerator over each denominator is a rational zero.... +/- 1/1, +/- 2/1, +/- 4/1, +/- 8/1, +/- 1/2, +/- 2/2, +/- 4/2, and +/- 8/2
Simplified: +/- 1, +/- 2, +/- 4, +/- 8, +/- 1/2, +/-1, +/- 2, and +/- 4

There are some duplicates so you can "drop" them... So your final answer is:

+/- 1/2, +/- 1, +/- 2, +/- 4, +/- 8

Answer 5

omg
this is so confusing

Answer 6

f(x) = -2x^4 + 4x^3 + 3x^2 + 18
constant term?
Factors of the leading coefficient?

Answer 7

http://softmath.com/tutorials-3/reducing-fractions/the-real-zeros-of-a-polynomial.html

Answer 8

factors of 2: 1,2
factors of 18: 1,2,3,4,6,18
so some examples include 1/1,1/2,2/1,2/2,3/1,3/2,...

Answer 9

ok

Answer 10

so what are constant term?
Factors of the leading coefficient?
and do i need to do that for every number?

Answer 11

@jenny1003

Answer 12

-2 and 18 Sorry I'm helping alot of ppl at the same time

Answer 13

factors of 2: 1,2
factors of 18: 1,2,3,4,6,18
factors of 4: 1,2,4
factors of 13: 1,3,

Answer 14

3 not 13

Answer 15

The leading term of a polynomial is the term of highest degree.
The leading coefficient of a polynomial is the coefficient of the leading term.
The degree of a polynomial is the degree of the leading term.

Answer 16

leading term 4
leading coefficient -2

Answer 17

I'm lost right now

Answer 18

i am too

Answer 19

@200205650 Please help....Srry

Answer 20

http://www.mcg.net/nelson/CHAT/math/precalculus/overheads/sec.%202.5.pdf

Answer 21

So you are pretty much solving for x in this equation right?

Answer 22

i don't really know :O

Answer 23

@ParthKohli

Answer 24

http://www.virtualnerd.com/tutorials/?id=Alg2_06_01_0020

Answer 25

This video might help in solving this problem. And yes you are trying to find what are all the numbers that can equal x. Factoring is one way of solving this problem. I can help you if you don't know how to factor this problem.

Answer 26

@ganeshie8 @nincompoop

Answer 27

@Peaches15

Answer 28

@DanTheMan99

Answer 29

i just saw the video, but still i can't understand

Answer 30

Did you watch the whole thing?

Answer 31

yes

Answer 32

jk

Answer 33

i didn't

Answer 34

i saw the beginning

Answer 35

Okay why don't you watch that video and I'll try to solve this problem using factoring. Is that fine?

Answer 36

thank you

Answer 37

No problem!

Answer 38

@DanTheMan99 check this out

http://www.wolframalpha.com/input/?i=f%28x%29+%3D+-2x%5E4+%2B+4x%5E3+%2B+3x%5E2+%2B+18

Answer 39

\[-2x^4+4x^3+3x^2+18\]\[-2x^3(x-2)+3(x^2+6)\]\[(-2x^3+3)(x-2)(x^2+6)\]
Equation #1:\[(-2x^3+3)=0\]\[-2x^3=-3\]\[x^3=\frac{ 3 }{ 2 }\]\[x=0.72112\]
Equation#2: \[(x-2)=0\]\[x=2\]
Equation #3:\[(x^2+6)=0\]\[x^2=-6\]\[x=\sqrt{6}i\]

Answer 40

thank you guys so much

Answer 41

You're welcome!

Answer 42

Greatly done, @200205650

Answer 43

Thanks!

Answer 44

+ 1/2, + 1, + 2, + 4, + 8, - 1/2, - 1, - 2, - 4, and -8.

Answer 45

i don't know how to answer

Answer 46

like how to put it into words

Answer 47

ugh

Answer 48

@nono266 please help me

Answer 49

what should i write

Answer 50

you have it written fine

Answer 51

i know
but whats my explanation

Answer 52

like what proof can i give

Answer 53

there is no need to do so

Answer 54

are you sure

Answer 55

100% positive

Answer 56

is this flvs?

Answer 57

yeah

Answer 58

ok then yeah you do not need to

Answer 59

for sure

Answer 60

it is fine if you have the right answer then they know you understand it

Answer 61

ok
thanks

Answer 62

do i get 10 owl bucks because i need them

Answer 63

?????????????

Answer 64

do you have paypal?

Answer 65

no

Answer 66

can you ask the question for me and i go under it. ask a qualified helper question

Answer 67

ask the question as ALGEBRA 1 HELP THEN I WILL ADD THE REST