a loan earns interest at a certain rate (compound)per cent per annum.four years ago the amount was rs.81 ;now it is rs.144.what will the amount be two years hence?
Use the formula and plug in the values.
\[A=P(1+\frac{ r }{ 100 })^n\]
dude i know the formula but this sum is different
basically we neither have p value nor t nor r only we have is two compound interest amount
you have P, A and n
where do you see p and 81 and 144 are compound interest amount and not the total amount
it is the interest+year 0 p
u solve the problem if you can and pls give me the steps coz i can't
first rearrange the formula and put r to one side
\[144=81(1+\frac{ r }{ 100 })^4\] \[\frac{ 144 }{ 81 }=(1+\frac{ r }{ 100 })^4\]
\[\frac{ 16 }{ 9 } = (1+\frac{ r }{ 100 })^4\]
\[\frac{ 4 }{ 3 } = (1 + \frac{ r }{ 100 })^2\]
\[\frac{ 4 }{ 3 } = 1+ \frac{ r }{ 50 } + \frac{ r^2 }{ 10000 }\]\[-\frac{ 1 }{ 3 } = \frac{ r }{ 50 } + \frac{ r }{ 10000 }\]
i do not think this is ok...coz the answer given id 191.40
some typos there
ok thanks anyways
mines 15.47
no its 191.40
thanks for you try
the interest rate is 15.47
so the 2 years stuff its up to you to try
i'm so sorry saseal pls don't mind your calculation was absolutely correct .....i understood the sum a little later thanks dude thank you so much
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