How many different four-digit numbers can be made using the digits 1, 2, 3, 4, 5, 6 if no digit can be used more than once?

Question

anonymous · Answer

please help me!!
@jcoury 
@OregonDuck

oregonduck · Answer

what do you think?

anonymous · Answer

im not sure!! like idk how to even solve for it. thats what i need help with.

oregonduck · Answer

60 is the answer

oregonduck · Answer

it seems endless though lol :)

anonymous · Answer

are you serious??!! how do you know this stuff??! lol.

oregonduck · Answer

i may be wrong am i @kropot72 ?

kropot72 · Answer

There are 6 choices for the first selection. Having chosen one number there are 5 choices for the second number, 4 choices for the third and 3 choices for the fourth.
Therefore the number of four digit numbers is given by:
$$\large 6\times5\times4\times3=you\ can\ calculate$$

anonymous · Answer

360?! yess thats an option! thankyou!

kropot72 · Answer

You're welcome :)

oregonduck · Answer

360 is correct

anonymous · Answer

shouldn't it be 6*5*4*3*2?

oregonduck · Answer

never doubt a champ

kropot72 · Answer

@niels5x9 Why do you think that?

anonymous · Answer

because first you have six options then you have five options then four then three and finally two right?

anonymous · Answer

oh oops 4 digit numbers i faileded

kropot72 · Answer

Never mind :)